A body starts from rest and moves under constant acceleration for 20 s. It covers distance S_1 in the first 10 s and S_2 in the next 10 s. Then S_2 equals:

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NEET Physics QUESTION #7300

Question 1

A body starts from rest and moves under constant acceleration for 20 s. It covers distance $S_1$ in the first 10 s and $S_2$ in the next 10 s. Then $S_2$ equals:

$S_1$
$2S_1$
$3S_1$✔️
$4S_1$

Correct Answer Explanation

Using $s = \dfrac{1}{2}at^2$ (from rest):

$S_1 = \dfrac{1}{2}a(10)^2 = 50a$

Total in 20 s: $S_{\text{total}} = \dfrac{1}{2}a(20)^2 = 200a$

$S_2 = 200a - 50a = 150a = 3 \times 50a = \mathbf{3S_1}$

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