The displacement of a particle is given by s = t^3 - 6t^2 + 3t + 4 metres. The velocity when acceleration is zero is:

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NEET Physics QUESTION #7303

Question 1

The displacement of a particle is given by $s = t^3 - 6t^2 + 3t + 4$ metres. The velocity when acceleration is zero is:

Correct Answer Explanation

$v = \dfrac{ds}{dt} = 3t^2 - 12t + 3$

$a = \dfrac{dv}{dt} = 6t - 12$

Setting $a = 0$: $t = 2\text{ s}$

$v\big|_{t=2} = 3(4) - 12(2) + 3 = 12 - 24 + 3 = \mathbf{-9\text{ m/s}}$