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NEET Physics QUESTION #7308
Question 1

A particle starts from rest and moves with constant acceleration. After some time it decelerates and comes to rest. If it travels $S_1$ in first 10 s and $S_2$ in the next 10 s (from rest, constant acceleration), then $S_2 : S_1$ is: (This is a standard ratio-of-distances problem for uniformly accelerated motion from rest.)

  • $1:1$
  • $3:1$✔️
  • $4:1$
  • $2:1$
Correct Answer Explanation

Using $s = \dfrac{1}{2}at^2$: $S_1 = 50a$, total in 20 s $= 200a$, so $S_2 = 150a$.

$S_2 : S_1 = 150a : 50a = \mathbf{3:1}$