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NEET Physics QUESTION #7313
Question 1

A particle moves such that $x = (t+5)^{-1}$. The acceleration of the particle is proportional to:

  • $(\text{velocity})^{2/3}$
  • $(\text{velocity})^{3/2}$✔️
  • $(\text{distance})^{2}$
  • $(\text{distance})^{-2}$
Correct Answer Explanation

$v = \dfrac{dx}{dt} = -(t+5)^{-2}$, so $(t+5) = (-v)^{-1/2}$

$a = \dfrac{dv}{dt} = 2(t+5)^{-3} = 2(-v)^{3/2}$

Therefore $a \propto \mathbf{(\text{velocity})^{3/2}}$