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NEET Physics
QUESTION #7315
Question 1
A stone is dropped from rest from the top of a $20\text{ m}$ tower. Its speed on hitting the ground is ($g = 10\text{ m/s}^2$):
Correct Answer Explanation
Using $v^2 = u^2 + 2gh = 0 + 2(10)(20) = 400$
$v = \sqrt{400} = \mathbf{20\text{ m/s}}$
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