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NEET Physics QUESTION #7316
Question 1

A body moves eastward at $30\text{ m/s}$. After 10 s its velocity becomes $40\text{ m/s}$ northward. The magnitude of average acceleration is:

  • $1\text{ m/s}^2$
  • $7\text{ m/s}^2$
  • $\sqrt{7}\text{ m/s}^2$
  • $5\text{ m/s}^2$✔️
Correct Answer Explanation

Change in velocity: $\Delta\vec{v} = 40\hat{j} - 30\hat{i}$

$|\Delta v| = \sqrt{30^2 + 40^2} = \sqrt{900+1600} = \sqrt{2500} = 50\text{ m/s}$

Average acceleration $= \dfrac{50}{10} = \mathbf{5\text{ m/s}^2}$