Back to Questions
NEET Physics
QUESTION #7319
Question 1
A stone dropped from height $h$ hits the ground with momentum $P$. If the same stone is dropped from height $2h$ (100% more), the momentum on hitting the ground changes by approximately:
Correct Answer Explanation
$v = \sqrt{2gh}$, so $P = mv = m\sqrt{2gh}$
New momentum: $P' = m\sqrt{2g(2h)} = \sqrt{2}\,P$
Percentage change $= (\sqrt{2}-1)\times 100 \approx 0.414 \times 100 = \mathbf{41\%}$
Sign in to join the conversation and share your thoughts.
Log In to Comment