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NEET Physics QUESTION #7332
Question 1

A projectile is thrown at angles $(45°-\theta)$ and $(45°+\theta)$ with the horizontal. The ratio of their horizontal ranges is:

  • $1:1$✔️
  • $2:3$
  • $1:2$
  • $2:1$
Correct Answer Explanation

Using $R = \dfrac{u^2\sin2\alpha}{g}$:

$R_1 = \dfrac{u^2\sin(90°-2\theta)}{g} = \dfrac{u^2\cos2\theta}{g}$

$R_2 = \dfrac{u^2\sin(90°+2\theta)}{g} = \dfrac{u^2\cos2\theta}{g}$

$R_1 : R_2 = \mathbf{1:1}$