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NEET Physics
QUESTION #7333
Question 1
A particle starts from the origin (0, 0) and moves in a straight line. At a later time its position is $(\sqrt{3},\,3)$. The angle the path makes with the positive $x$-axis is:
Correct Answer Explanation
$\tan\alpha = \dfrac{y}{x} = \dfrac{3}{\sqrt{3}} = \sqrt{3}$
$\alpha = \tan^{-1}(\sqrt{3}) = \mathbf{60°}$
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