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NEET Physics QUESTION #7340
Question 1

The horizontal range and maximum height of a projectile are equal. The angle of projection is:

  • $\theta = \tan^{-1}(2)$
  • $\theta = 45°$
  • $\theta = \tan^{-1}\!\left(\dfrac{1}{4}\right)$
  • $\theta = \tan^{-1}(4)$✔️
Correct Answer Explanation

$R = H \Rightarrow \dfrac{u^2\sin2\theta}{g} = \dfrac{u^2\sin^2\theta}{2g}$

$4\sin\theta\cos\theta = \sin^2\theta \Rightarrow 4\cos\theta = \sin\theta \Rightarrow \tan\theta = 4$

$\theta = \mathbf{\tan^{-1}(4)}$