A projectile is launched from the ground with initial velocity vec u = u_0hat i + v_0hat j . Gravity acts in the -y direction. The maximum displacement in the x-direction is:

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NEET Physics QUESTION #7343

Question 1

A projectile is launched from the ground with initial velocity $\vec{u} = u_0\hat{i} + v_0\hat{j}$. Gravity acts in the $-y$ direction. The maximum displacement in the $x$-direction is:

$\dfrac{u_0^2}{2g}$
$\dfrac{2u_0 v_0}{g}$✔️
$\dfrac{v_0^2}{2g}$
$\dfrac{4u_0 v_0}{g}$

Correct Answer Explanation

Time of flight $= \dfrac{2v_0}{g}$ (time for vertical displacement to return to zero).

Horizontal range $= u_0 \times \dfrac{2v_0}{g} = \mathbf{\dfrac{2u_0 v_0}{g}}$

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