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NEET Physics
QUESTION #7344
Question 1
A projectile from Earth (speed $5\text{ m/s}$ at angle $\theta$) follows the same trajectory as one from another planet (speed $3\text{ m/s}$, same angle). The gravitational acceleration on that planet is ($g_{\text{Earth}} = 9.8\text{ m/s}^2$):
Correct Answer Explanation
For identical trajectories at the same angle, the ratio $\dfrac{u^2}{g}$ must be equal (since all trajectory dimensions scale with $u^2/g$):
$\dfrac{25}{9.8} = \dfrac{9}{g'} \Rightarrow g' = \dfrac{9 \times 9.8}{25} = \dfrac{88.2}{25} \approx \mathbf{3.5\text{ m/s}^2}$
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