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ECAT Physics QUESTION #742
Question 1
If the distance is doubled between two charges then Coulomb's force becomes:
  • Doubled
  • Half
  • Reduced 4 times✔️
  • Remains same
Correct Answer Explanation
By Coulomb's law F = kq1q2/r². If r is doubled F = kq1q2/(2r)² = F/4. Force reduces to one-fourth.