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EEJ MAIN Mathematics QUESTION #7485
Question 1
Let a function \(f:(0,\infty) \to (0,\infty)\) be defined by \(f(x) = |1-\frac{1}{x}|\). Then f is:
  • not injective but it is surjective
  • injective only
  • neither injective nor surjective✔️
  • both injective as well as surjective
Correct Answer Explanation
We have \(f(x) = |1-\frac{1}{x}| = \begin{cases} 1-\frac{1}{x} & \text{if } x>1 \\ \frac{1}{x}-1 & \text{if } 01\) is \([0,1)\), and for \(0