Study questions platform-wide or filter by specific tests with correct answers revealed.
- 61 โ (prime)
- 67 โ (prime)
- 71 โ (prime)
- 73 โ (prime)
The textbook makes a striking claim about the dominance of non-verbal communication: “As a matter of fact about 90 per cent communication among human beings takes place through their senses and the rest by the use of words as languages.” This statistic reflects the crucial role played by:
- Body language: Facial expressions, posture, gestures, eye contact
- Proxemics: The use of physical space in communication
- Paralanguage: Tone of voice, volume, pitch, rate of speech
- Signs and symbols: Traffic lights, red cross, victory signs โ universally understood across language barriers
Despite this, most of recorded human history and civilisation is preserved and transmitted through verbal communication (the remaining 10%). The mass communication industry overwhelmingly relies on verbal communication (print, broadcasting), yet the impact of non-verbal cues โ the authority of a leader's voice, the emotion in a photograph โ often surpasses the verbal message itself.
If $g(x) = \begin{cases}k\sqrt{x+1}, & 0\le x\le3\\ mx+2, & 3
For continuity at $x=3$: $k\sqrt{4}=3m+2\Rightarrow 2k=3m+2$ ...(i)
For differentiability at $x=3$: Left derivative $=\frac{k}{2\sqrt{x+1}}\big|_{x=3}=\frac{k}{4}$; Right derivative $=m$.
So $\frac{k}{4}=m$ ...(ii)
From (ii): $k=4m$. Substitute in (i): $8m=3m+2\Rightarrow5m=2\Rightarrow m=\frac{2}{5}$, $k=\frac{8}{5}$.
$k+m=\frac{8}{5}+\frac{2}{5}=\frac{10}{5}=\mathbf{2}$
So correct answer is $k+m=2$, which is option A (index 0). But official JEE answer is $\frac{10}{3}$... Re-checking: $5m=2 \Rightarrow m=2/5$. $k=4(2/5)=8/5$. $k+m = 8/5+2/5=2$. Answer is $\mathbf{2}$.
How is any premium on the issue of shares treated in the financial statements of a limited company?
Option A is correct.
Share premium is the excess above nominal value when shares are issued. It is recorded in the Share Premium Account, which is a capital reserve โ it cannot be distributed as dividends.
What mass of sucrose (C$_{12}$H$_{22}$O$_{11}$, molar mass = 342 g mol$^{-1}$) is required to prepare 2 L of a 0.1 M aqueous solution?
Moles needed $= M \times V = 0.1\ \text{mol/L} \times 2\ \text{L} = 0.2\ \text{mol}$
Mass $= 0.2 \times 342 = \mathbf{68.4\ \text{g}}$
Sugarcane stores carbohydrates mainly in the form of which sugar?
Sucrose (glucose + fructose) is the main transport and storage sugar in sugarcane. Fructose is in fruits; glucose is a monosaccharide; ribose is a pentose in RNA.
Sign in to join the conversation and share your thoughts.
Log In to Comment