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In Acute Myocardial Infarction (AMI), the priority nursing assessment is continuous cardiac monitoring and 12-lead ECG because:
- AMI causes life-threatening arrhythmias (ventricular fibrillation, ventricular tachycardia) in the first hours
- ECG identifies the infarct location, extent, and guides reperfusion decisions
- Time-to-treatment (door-to-balloon time โค 90 minutes for STEMI) is the key determinant of outcomes
The 4 Ts of AMI nursing priority:
- Time (ECG within 10 minutes)
- Thrombolytics/PCI preparation
- Therapy (MONA: Morphine, Oxygen, Nitrates, Aspirin)
- Telemetry (continuous cardiac monitoring)
Cardiac biomarkers (Troponin I/T) are diagnostic but take time. ECG provides immediate actionable information.
\(\text{Cl}_2 > \text{Br}_2 > \text{F}_2 > \text{I}_2\)
Fโ has an anomalously low bond energy (158 kJ/mol) due to lone pair repulsion in the small F atom, making \(\text{Cl}_2\) stronger. So the order \(\text{F}_2 > \text{Cl}_2\) for bond dissociation energy is incorrect.
All other options are correct: oxidising power, acid strength of HX in water, and electronegativity all follow the stated orders.
Set revenue $\geq$ cost:
$500x \geq 9{,}000 + 400x$
$100x \geq 9{,}000$
$x \geq 90$
The minimum number of refrigerators is $\mathbf{90}$.
Of the following, which is closest to $\sqrt[3]{30}$?
Estimate by testing perfect cubes:
- $2^3 = 8$
- $3^3 = 27$
- $4^3 = 64$
Since $27 < 30 < 64$, we know $3 < \sqrt[3]{30} < 4$.
$30$ is much closer to $27$ than to $64$, so $\sqrt[3]{30}$ is closer to $3$ than to $4$.
More precisely: $\sqrt[3]{30} \approx 3.107$
Among the options $\{6, 5, 4, 3\}$, the value $3$ is closest.
Given a circle $2x^2+2y^2=5$ and a parabola $y^2=4\sqrt{5}\,x$, consider:
Statement I: A common tangent is $y=x+\sqrt{5}$.
Statement II: If $y=mx+\frac{\sqrt{5}}{m}$ is a common tangent, then $m^4-3m^2+2=0$.
For the parabola $y^2=4\sqrt{5}x$: tangent in slope form is $y=mx+\frac{\sqrt{5}}{m}$.
For the circle $x^2+y^2=5/2$ (radius $\sqrt{5/2}$): distance from origin to tangent $= \frac{|\sqrt{5}/m|}{\sqrt{1+m^2}}=\sqrt{5/2}$
$\frac{5/m^2}{1+m^2}=\frac{5}{2}\Rightarrow\frac{1}{m^2(1+m^2)}=\frac{1}{2}\Rightarrow m^2+m^4=2\Rightarrow m^4+m^2-2=0$
Hmm: $m^4+m^2-2=(m^2+2)(m^2-1)=0$, so $m=\pm1$. Statement II gives $m^4-3m^2+2=0=(m^2-1)(m^2-2)=0$, so $m=\pm1,\pm\sqrt{2}$ โ this is different. But $m=\pm1$ works for both. At $m=1$: tangent is $y=x+\sqrt{5}$ โ. Statement I is true; Statement II is false (wrong equation).
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