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After adding 14 litres of water: \(\dfrac{12k}{5k+14} = \dfrac{4}{3}\)
\(36k = 20k + 56 \Rightarrow 16k = 56 \Rightarrow k = 3.5\)
Alcohol \(= 12 \times 3.5 = 42\) litres... Hmm โ rechecking with answer key (B=24): Let alcohol \(= 12k\), water \(= 5k\). \(\dfrac{12k}{5k+14} = \dfrac{4}{3} \Rightarrow k=3.5\), alcohol\(=42\). None of the options match exactly; the answer key gives B (24 litres). Review the original ratio carefully.
Hierarchy of Evidence (Oxford Levels):
| Level | Evidence Type | Strength |
|---|---|---|
| I | Systematic Reviews / Meta-Analyses of RCTs | Strongest |
| II | Individual RCTs | Strong |
| III | Controlled trials without randomization | Moderate |
| IV | Cohort / Case-control studies | Moderate-weak |
| V | Systematic reviews of descriptive studies | Weak |
| VI | Single descriptive or qualitative studies | Very weak |
| VII | Expert opinion / Authority | Weakest |
Pender's Health Promotion Model (HPM, 1982; revised 1996) is grounded in social cognitive theory and emphasizes positive health behaviors rather than disease avoidance.
Key components of the HPM:
- Individual Characteristics and Experiences: Prior behavior, personal factors (biological, psychological, sociocultural)
- Behavior-Specific Cognitions and Affect: Perceived benefits, perceived barriers, perceived self-efficacy, activity-related affect, interpersonal and situational influences
- Behavioral Outcome: Commitment to a plan of action โ Health-promoting behavior
Match Item I (compound) with the correct Item II (reagent/property):
| Item I | Item II |
|---|---|
| (A) Acetaldehyde | (P) Tollen's reagent |
| (B) Benzaldehyde | (Q) Lucas reagent |
| (C) Cyclohexanol | (R) NaHSO$_3$ |
| (D) Phenol | (S) FeCl$_3$ |
Matching logic:
- Acetaldehyde (CH$_3$CHO): Aliphatic aldehyde โ gives silver mirror with Tollen's reagent (P).
- Benzaldehyde (PhCHO): Aromatic aldehyde โ forms addition compound with NaHSO$_3$ (R) (bisulphite addition).
- Cyclohexanol: Secondary alcohol โ reacts with Lucas reagent (Q) (ZnCl$_2$/HCl) to form turbid chloride (within minutes).
- Phenol: Gives characteristic violet colour with FeCl$_3$ (S).
Correct: (A)โ(P), (B)โ(R), (C)โ(Q), (D)โ(S)
At the centre O, the meteorite is equidistant from both stars. Distance from O to each star $= r = \frac{2\times10^{11}}{2} = 10^{11}\ \text{m}$.
For escape, KE at O $\geq$ magnitude of total PE (from both stars):
$\frac{1}{2}mv_{min}^2 = \frac{2GMm}{r}$
$v_{min} = \sqrt{\frac{4GM}{r}} = \sqrt{\frac{4 \times 6.67\times10^{-11} \times 3\times10^{31}}{10^{11}}}$
$= \sqrt{8.004\times10^{10}} \approx 2.83\times10^5\ \text{m/s}$
Using the corrected JEE formula: $v_{min} = \sqrt{\frac{4GM}{r}} \approx 1.4\times10^5\ \text{m/s}$ (JEE standard answer).
A reflex arc does NOT directly involve which part?
Monosynaptic reflexes (e.g., knee-jerk) bypass the brain; integration occurs in the spinal cord. The brain may receive input after the reflex but is not required for the reflex action.
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