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Disproportionation occurs when an element in a specific oxidation state can be both oxidized and reduced. This requires the element to be in an intermediate oxidation state.
- In $BrO_{4}^{-}$, the oxidation state of Bromine is $+7$.
- Since $+7$ is the maximum possible oxidation state for Bromine, it cannot be oxidized further.
- Therefore, $BrO_{4}^{-}$ cannot undergo disproportionation.
In the context of HRM challenges, 'consistency' is particularly important in:
HR policies help maintain consistency and equity, which is particularly important in compensation and promotion decisions. Without HR department coordination, salary structures become uneven and unfair, and promotion decisions may be handled inequitably.
Which of the bromine oxoanion species does NOT undergo disproportionation?
Disproportionation occurs when an element in an intermediate oxidation state simultaneously undergoes oxidation and reduction.
- $\text{BrO}^-$ (Br = +1): can disproportionate to Br$^-$ ($-1$) and BrO$_3^-$ ($+5$) ✓
- $\text{BrO}_2^-$ (Br = +3): can disproportionate to $\text{BrO}^-$ and $\text{BrO}_3^-$ ✓
- $\text{BrO}_3^-$ (Br = +5): can disproportionate under certain conditions ✓
- $\text{BrO}_4^-$ (Br = +7): Br is in its highest oxidation state for bromine — it cannot be further oxidised, so disproportionation is not possible.
$\text{BrO}_4^-$ does not undergo disproportionation.
The formula for the sampling interval in systematic random sampling is:
\[k = \frac{N}{n}\]
Where:
- \(N\) = population size = 400
- \(n\) = desired sample size = 50
The nurse randomly selects a starting point between 1 and 8, then selects every 8th patient thereafter (e.g., patient 5, 13, 21, 29...). This method ensures equal probability of selection and is more practical than simple random sampling for large populations.
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