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Math Physics Chemistry Biology QUESTION #575
Question 7221
In __________ zone the light is insufficient to support photosynthesis.
  • Desert
  • Profundalβœ”οΈ
  • Littoral
  • All of these
Correct Answer Logic:
Profundal zone lacks sufficient light
Uploaded by: Fani Warraich
Math Physics Chemistry Biology QUESTION #571
Question 7222
How many grams of nitrogen can be eliminated in form of uric acid by 50 ml of water?
  • 20
  • 25
  • 30
  • 50βœ”οΈ
Correct Answer Logic:
50 ml water can eliminate ~50g nitrogen as uric acid
Uploaded by: Fani Warraich
Reading and Writing (Module-1) QUESTION #10455
Question 7223
The tribunal's ruling was ------- , announced without explanation and allowing no opportunity for -------.
  • deliberative . . discussion
  • peremptory . . appealβœ”οΈ
  • consultative . . debate
  • negotiable . . revision
Correct Answer Logic:
A ruling with no explanation and no chance to challenge it is 'peremptory,' allowing no 'appeal.'
Uploaded by: Fani Warraich
English QUESTION #2759
Question 7224
Which sentence is correctly PUNCTUATED?
  • What time does the train leave.
  • What time does the train leave?βœ”οΈ
  • What time does the train leave!
  • What time does the train leave;
Correct Answer Logic:
An interrogative sentence (question) must end with a question mark (?). 'What time does the train leave?' is correctly punctuated.
Uploaded by: Fani Warraich
Electrical Engineering QUESTION #2174
Question 7225
In LQR optimal control, the cost $J = \int_0^\infty (x^TQx + u^TRu)\,dt$ is minimized by $u^* = -Kx$ where $K = R^{-1}B^TP$. The positive-definite matrix $P$ satisfies:
  • The Algebraic Riccati Equation: $PA + A^TP - PBR^{-1}B^TP + Q = 0$βœ”οΈ
  • The Lyapunov equation: $PA + A^TP + Q = 0$
  • The Sylvester equation: $AP + PA^T = -Q$
  • The Hamiltonian eigenvalue problem only
Correct Answer Logic:
The steady-state matrix $P$ in LQR is the unique positive-definite solution of the Algebraic Riccati Equation (ARE): $PA + A^TP - PBR^{-1}B^TP + Q = 0$, from which the optimal gain $K = R^{-1}B^TP$ is derived.
Uploaded by: Fani Warraich
English QUESTION #2651
Question 7226
Change the sentence to active voice: 'The window was broken by the boy.'
  • The boy breaks the window.
  • The boy had broken the window.
  • The boy broke the window.βœ”οΈ
  • The boy is breaking the window.
Correct Answer Logic:
The passive 'was broken' indicates Simple Past, so the active verb must be 'broke'.
Uploaded by: Fani Warraich
General Knowledge QUESTION #8692
Question 7227
When was the People's Republic of China founded?
  • 1947
  • 1948
  • 1949βœ”οΈ
  • None of above
Correct Answer Logic:
Communist China was founded on October 1, 1949.
Uploaded by: Fani Warraich
Correct Answer Logic:
For two lines to be coplanar, the scalar triple product of their direction ratios and the vector joining points on the lines must be zero. The direction ratios are \((1, 1, -k)\) and \((k, 2, 1)\). A point on the first line is \((2, 3, 4)\) and on the second is \((1, 4, 5)\). The vector joining them is \((-1, 1, 1)\). Setting up the determinant: \(\begin{vmatrix} -1 & 1 & 1 \\ 1 & 1 & -k \\ k & 2 & 1 \end{vmatrix} = 0\). Expanding: \(-1(1+2k) - 1(1+k^2) + 1(2-k) = 0\), which simplifies to \(k^2 + 3k = 0\), giving \(k = 0\) or \(k = -3\). Thus, k has exactly two values.
Uploaded by: Fani Warraich
Correct Answer Logic:
We have \(m = \frac{\ell+n}{2}\). For three geometric means between \(\ell\) and \(n\), we have \(\ell, G_1, G_2, G_3, n\) in G.P. The common ratio is \(r = (\frac{n}{\ell})^{1/4}\). Thus \(G_1 = \ell r = \ell(\frac{n}{\ell})^{1/4}\), \(G_2 = \ell r^2 = \ell\sqrt{\frac{n}{\ell}} = \sqrt{\ell n}\), \(G_3 = \ell r^3 = \ell(\frac{n}{\ell})^{3/4}\). We get \(G_2^2 = \ell n\) and \(G_1 \cdot G_3 = \ell^2 r^4 = \ell n\). Therefore \(G_1^4 + 2G_2^4 + G_3^4 = (G_1^2)^2 + 2(\ell n)^2 + (G_3^2)^2\). Using \(G_1^2 + G_3^2 = (\ell r)^2 + (\ell r^3)^2 = \ell^2 r^2(1+r^4) = \ell^2(\frac{n}{\ell})^{1/2}(1+\frac{n}{\ell}) = \ell n^{1/2}(\frac{\ell+n}{\ell}) = n^{1/2}(\ell+n)\). After careful calculation, the answer is \(4\ell m^2 n\).
Uploaded by: Fani Warraich
Chemistry QUESTION #7822
Question 7230

Which molecule has zero dipole moment?

  • BFβ‚ƒβœ”οΈ
  • NF₃
  • NH₃
  • Hβ‚‚O
Correct Answer Logic:

BF₃ is trigonal planar with symmetric bond dipoles canceling (net ΞΌ=0). NF₃, NH₃, Hβ‚‚O are polar.

Uploaded by: Fani Warraich
Biology Zoology Botany QUESTION #10780
Question 7231
Which is considered the largest single cause of biodiversity loss worldwide?
  • Habitat destructionβœ”οΈ
  • Hunting
  • Pollution
  • Disease
Correct Answer Logic:
Habitat destruction β€” including deforestation, wetland drainage, agricultural expansion, and urbanisation β€” is recognised as the greatest single threat to global biodiversity. It eliminates species' living space, food sources, and breeding areas, leading directly to population decline and extinction. The IUCN cites habitat loss as the primary threat to the majority of currently threatened species, far outweighing hunting, pollution, invasive species, and climate change individually.
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General Knowledge QUESTION #11490
Question 7232
Which key removes the character located directly to the right of the insertion point?
  • End
  • Backspace
  • Home
  • Deleteβœ”οΈ
Correct Answer Logic:
The Delete key removes the character to the right of the cursor (forward deletion). The Backspace key removes the character to the left (backward deletion). Ctrl+Delete deletes the word to the right; Ctrl+Backspace deletes the word to the left.
Uploaded by: Fani Warraich
English QUESTION #8418
Question 7233
His silence _______ to refusal.
  • Tantamounts
  • is tantamountβœ”οΈ
  • is tantamounting
  • tantamounted
Correct Answer Logic:
'Is tantamount to' means is equivalent to.
Uploaded by: Fani Warraich
Pakistan Affairs QUESTION #9110
Question 7234
The Sir Creek channel is a disputed area between Pakistan and India. Where is it located?
  • Punjab & Indian Punjab
  • Punjab & Himachal Pradesh
  • Sindh & Indian Gujaratβœ”οΈ
  • None of above
Correct Answer Logic:
Sir Creek is in the Rann of Kutch between Sindh and Gujarat.
Uploaded by: Fani Warraich
General Knowledge QUESTION #4655
Question 7235
Returning from a movie, you see people chasing two girls in a cab. What will you do?
  • Pass on your way quietlyβœ”οΈ
  • Ask the people to run away or face consequences
  • Seek help from passerby to help the girls
  • Escort girls to market place
Correct Answer Logic:
1
Uploaded by: Fani Warraich
Geology QUESTION #10640
Question 7236
During daylight hours, the sea breeze direction is:
  • From land toward the sea
  • From sea toward the landβœ”οΈ
  • From sea toward the land at night only
  • From land toward the sea at night only
Correct Answer Logic:
During the day, land heats up faster than the sea (lower heat capacity), causing air above the land to warm, rise, and create a low-pressure zone. Cooler, denser air from the sea flows in to replace it β€” producing a sea breeze blowing from sea to land. At night, the process reverses: land cools faster, the sea is relatively warmer, and a land breeze blows from land to sea.
Uploaded by: Fani Warraich
General Knowledge QUESTION #8742
Question 7237
The Equator, the Tropic of Cancer, and the Tropic of Capricorn all pass through which continent?
  • Africaβœ”οΈ
  • Asia
  • South America
  • None above
Correct Answer Logic:
All three major circles of latitude pass through Africa.
Uploaded by: Fani Warraich
Correct Answer Logic:
For a web plate with no transverse stiffeners (pure shear panel, \(a/h \to \infty\)), the shear buckling coefficient is \(k_v = 5.34\). When transverse stiffeners are present with aspect ratio \(a/h \leq 1\): \(k_v = 4.0 + \dfrac{5.34}{(a/h)^2}\). The critical shear stress is \(F_{cr} = \dfrac{k_v \pi^2 E}{12(1-\nu^2)(h/t_w)^2}\). AISC uses \(k_v = 5.34\) as the baseline for unstiffened webs.
Uploaded by: Fani Warraich
Math Physics Chemistry Biology QUESTION #4254
Question 7239
Neurosecretory cells are:
  • endocrine cells
  • exocrine cells
  • neuroglial cells
  • neurons that have been adapted to secrete hormonesβœ”οΈ
Correct Answer Logic:
Neurosecretory cells are specialized neurons that secrete hormones.
Uploaded by: Fani Warraich
Correct Answer Logic:

We use the property: $|adj(A)| = |A|^{n-1}$ for an $n\times n$ matrix. Here $n=3$, so $|P| = |A|^2 = 16$.

Compute $|P|$ by expanding along row 1 (with unknown $\alpha$):

$|P| = 1(3\cdot4-3\cdot4) - \alpha(1\cdot4-3\cdot2) + 3(1\cdot4-3\cdot2)$

$= 1(0) - \alpha(4-6) + 3(4-6) = 2\alpha - 6$

Setting $2\alpha - 6 = 16 \Rightarrow 2\alpha = 22 \Rightarrow \alpha = \mathbf{11}$

Uploaded by: Fani Warraich