Circle: $x^2+y^2-4x+6y-12=0$ has centre $(2,-3)$ and radius $\sqrt{4+9+12}=5$.

A diameter of this circle is a chord of $S$. The diameter passes through $(2,-3)$ with length $10$, so the chord of $S$ has length $10$, meaning half-chord $=5$.

Centre of $S$ is $(-3,2)$. Distance from $(-3,2)$ to centre $(2,-3)$: $d=\sqrt{25+25}=5\sqrt{2}$.

The chord (diameter of inner circle) has its midpoint at $(2,-3)$, and $S$'s centre is at $(-3,2)$. Radius of $S$: $R=\sqrt{d^2+5^2}$... but wait: the diameter of the inner circle passes through $(2,-3)$. Distance from $(-3,2)$ to $(2,-3)$ is $5\sqrt{2}$. The chord (full diameter $=10$) is a chord of $S$, so $R^2=(5)^2+(5\sqrt{2})^2=25+50=75$, $R=5\sqrt{3}$.

Option B (2 and 3) is correct.

• Directors — manage the company, internal users.
• Employees — employed by the business, internal users.

Banks and potential investors are external users.

A credit purchase of inventory increases both current assets (inventory goes up) and current liabilities (accounts payable goes up) by the same amount. When the ratio is $> 1$, adding equal amounts to both numerator and denominator brings the ratio closer to 1 — i.e., it decreases. For example, if CA $= 200$ and CL $= 100$ (ratio $= 2$), adding 50 to each gives $250/150 \approx 1.67$ — lower but still above 1. So the ratio decreases but stays above 1.