The Objective Resolution, the cornerstone of Pakistan's constitutional history, was passed on March 12, 1949.

Option C is correct.

Margin of safety = Actual (or budgeted) sales revenue − Break-even sales revenue

It represents the buffer before the business starts making a loss.

• \(25 = 5^2\)
• \(30 = 2 \times 3 \times 5\)
• \(35 = 5 \times 7\)
• \(40 = 2^3 \times 5\)

The diagonal of the rectangle is 10 and one side is 6.

Using the Pythagorean theorem: $\text{diagonal}^2 = \text{length}^2 + \text{width}^2$

$10^2 = 6^2 + w^2 \Rightarrow 100 = 36 + w^2 \Rightarrow w^2 = 64 \Rightarrow w = 8$

Perimeter $= 2(6 + 8) = 2 \times 14 = 28$.

Since the battery is disconnected, charge $Q$ is constant:

$Q = C_0 V_0 = 12 \times 10^{-12} \times 10 = 120\ \text{pC}$

Initial energy: $U_i = \frac{Q^2}{2C_0} = \frac{(120\times10^{-12})^2}{2\times12\times10^{-12}} = 600\ \text{pJ}$

New capacitance: $C = KC_0 = 6.5 \times 12 = 78\ \text{pF}$

Final energy: $U_f = \frac{Q^2}{2C} = \frac{(120)^2 \times 10^{-24}}{2\times78\times10^{-12}} \approx 92.3\ \text{pJ}$

Work done by capacitor on slab $= U_i - U_f = 600 - 92.3 \approx 508\ \text{pJ}$

Distance in first 3 s: $s_3 = \dfrac{1}{2}(10)(3)^2 = 45\text{ m}$

Distance in last 1 s of total time $T$ (using $s_n = u + \dfrac{a}{2}(2n-1)$ with $u=0$):

$s_{\text{last}} = \dfrac{g}{2}(2T-1) = 5(2T-1)$

Setting equal: $5(2T-1) = 45 \Rightarrow 2T-1 = 9 \Rightarrow T = \mathbf{5\text{ s}}$