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Let $I_n=\displaystyle\int\tan^n x\,dx$ for $n>1$. If $I_4+I_6 = a\tan^5x + bx^5 + C$, find the ordered pair $(a,b)$.
Use the reduction: $I_n+I_{n-2}=\displaystyle\int\tan^{n-2}x\cdot\tan^2x\,dx+\int\tan^{n-2}x\,dx=\int\tan^{n-2}x\sec^2x\,dx=\dfrac{\tan^{n-1}x}{n-1}+C$
$I_4+I_6$: set $n=5$: $I_4+I_6=\dfrac{\tan^5x}{5}+C$
Comparing with $a\tan^5x+bx^5+C$: $a=\dfrac{1}{5}$, $b=0$.
$(a,b) = \left(\dfrac{1}{5},0\right)$
What happens to calcium ions when a skeletal muscle recovers (relaxes) after contraction?
During relaxation, Ca²⁺ is actively pumped back into the sarcoplasmic reticulum (SR) via Ca²⁺-ATPase (SERCA), lowering cytosolic Ca²⁺ and allowing tropomyosin to block myosin-binding sites.
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