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Let the junction temperature be $T$. In steady state, the heat current through the copper rod equals the sum of currents through brass and steel.
$\frac{K_c A (100 - T)}{L_c} = \frac{K_b A (T - 0)}{L_b} + \frac{K_s A (T - 0)}{L_s}$
$\frac{0.92 \times (100 - T)}{46} = \frac{0.26 \times T}{13} + \frac{0.12 \times T}{12}$
$0.02 (100 - T) = 0.02T + 0.01T \implies 2 - 0.02T = 0.03T \implies 5T = 200 \implies T = 40^\circ\text{C}$.
Rate of heat flow $H = \frac{0.92 \times 4 \times (100 - 40)}{46} = 0.02 \times 4 \times 60 = 4.8 \text{ cal/s}$.
If the arithmetic mean of 5 consecutive integers is 12, what is the sum of the least and greatest of these integers?
For 5 consecutive integers, the mean equals the middle (3rd) integer. So the middle integer is 12.
The 5 integers are: $10, 11, 12, 13, 14$.
The least is 10 and the greatest is 14.
Sum $= 10 + 14 = 24$.
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