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The owner of a firm used her own personal cash to buy office stationery for the business. Which account should be credited in the ledger?
When an owner introduces personal funds or assets into the business, it is treated as additional capital. The stationery account is debited (increase in expense), and the Capital account is credited (increase in owner's equity).
For a given solvent: elevation in boiling point for a 1 molal glucose solution is 2 K, and depression in freezing point for a 2 molal glucose solution is 2 K. What is the relation between $K_b$ and $K_f$?
Boiling point elevation: $\Delta T_b = K_b \cdot m$
$2 = K_b \times 1 \Rightarrow K_b = 2\ \text{K kg mol}^{-1}$
Freezing point depression: $\Delta T_f = K_f \cdot m$
$2 = K_f \times 2 \Rightarrow K_f = 1\ \text{K kg mol}^{-1}$
Therefore $K_b = 2 = 2K_f$, i.e., $\mathbf{K_b = 2\,K_f}$
Wait โ that gives option D. $K_b=2$ and $K_f=1$, so $K_b=2K_f$. But let me recheck: $\Delta T_b=K_b\cdot m_1$: $2=K_b\cdot1$, $K_b=2$. $\Delta T_f=K_f\cdot m_2$: $2=K_f\cdot2$, $K_f=1$. So $K_b=2K_f$. Official JEE answer is $K_b=K_f$ โ this would require $K_b=K_f=2$. In that case $\Delta T_f=2\times2=4\neq2$. The correct computation gives $K_b=2K_f$ (index 3).
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