Reading Mode - Questions

CISA QUESTION #1743

In risk management terminology, what is the precise distinction between a threat and a vulnerability?

Threats are the exploitable paths through which a vulnerability manifests.
Threats represent risks that convert into vulnerabilities only when they actually occur.
A vulnerability is an exploitable pathway or weakness that enables a threat to materialise and cause harm.✔️
A vulnerability is a negative event that will inevitably result in a loss when it takes place.

Correct Answer Logic:

A threat is any potential event or agent that could cause harm to an asset if it occurs. A vulnerability is a flaw, weakness, or gap in a system, process, or control that provides a pathway through which a threat can be realised. The two concepts are distinct but interdependent: a threat without a vulnerability cannot cause harm, and a vulnerability without a threat poses no immediate risk. Together, they define the concept of risk.

Uploaded by: Fani Warraich

General Abilities QUESTION #7986

Question 2

How many multiples of 9 that are less than 9999 are also perfect cubes?

5
6✔️
7
8

Correct Answer Logic:

Multiples of 9 that are perfect cubes: we need $n^3$ divisible by 9, i.e., $n^3$ divisible by $3^2$, which means $n$ divisible by 3.
Values: $n = 3, 6, 9, 12, 15, 18$ give $n^3 = 27, 216, 729, 1728, 3375, 5832$ — all less than 9999. That is 6 values.

Uploaded by: Fani Warraich

Math Physics Chemistry Biology QUESTION #4184

Question 3

When genes are linked, they tend to:

Segregate randomly
Cross over during meiosis
Stay together during inheritance✔️
Be inherited separately

Correct Answer Logic:

Linked genes are located on the same chromosome and tend to be inherited together.

Uploaded by: Fani Warraich

Chemistry QUESTION #5552

Question 4

According to Molecular Orbital Theory, which of the following species will NOT be a stable molecule?

$H_2^-$
$H_2^{2-}$✔️
$He_2^{2+}$
$He_2^+$

Correct Answer Logic:

Bond order for $H_2^{2-}$: 2 bonding + 2 antibonding electrons = BO = 0 → unstable. $H_2^-$: BO = 0.5 (stable). $He_2^{2+}$: 2 bonding, 0 antibonding electrons: BO = 1 (stable). $He_2^+$: BO = 0.5 (stable). Therefore $H_2^{2-}$ with BO = 0 is not a viable molecule.

Uploaded by: Fani Warraich

Civil Procedure QUESTION #3686

Question 5

A plaintiff (State A) sues a defendant (State B) in federal court for $\text{\$100,000}$. During the jury trial, at the close of the plaintiff's evidence, the defendant moves for Judgment as a Matter of Law (JMOL), which is denied. The jury returns a verdict for the plaintiff. The defendant then files a Renewed JMOL 10 days after the entry of judgment. The plaintiff objects, noting the defendant never moved for JMOL after the defendant's own evidence was presented. Is the Renewed JMOL proper?

Yes, because a motion for JMOL was made at some point during the trial.✔️
Yes, because a Renewed JMOL is always permitted within 28 days of judgment.
No, because a Renewed JMOL can only be filed if the party moved for JMOL at the close of all evidence.
No, because the defendant must show 'plain error' to renew the motion.

Correct Answer Logic:

Rule 50(b) requires that a party must have moved for JMOL under Rule 50(a) at some time during the trial to 'renew' it post-verdict. The 2006 amendments removed the requirement that the motion be made at the close of all evidence; it must simply be made before the case is submitted to the jury.

Uploaded by: Fani Warraich

Physics QUESTION #6987

Question 6

Two capacitors $C_1$ and $C_2$ are charged to 120 V and 200 V respectively. When connected together, the potential on each becomes zero. Which relation holds?

$5C_1 = 3C_2$
$3C_1 = 5C_2$✔️
$3C_1 + 5C_2 = 0$
$9C_1 = 4C_2$

Correct Answer Logic:

For the potential to become zero after connection, the total charge must be zero (charges cancel). Taking signs into account:

$Q_1 - Q_2 = 0 \Rightarrow C_1 \times 120 = C_2 \times 200$

$\frac{C_1}{C_2} = \frac{200}{120} = \frac{5}{3}$

$\Rightarrow 3C_1 = 5C_2$

The capacitors must have been charged with opposite polarities so that when connected, charges cancel. Conservation of charge gives $120C_1 = 200C_2$, yielding $3C_1 = 5C_2$.

Uploaded by: Fani Warraich

Islamic Studies QUESTION #653

Question 7

The battle of Nihawand was fought during the reign of:

Hazrat Abu Bakr
Hazrat Umar✔️
Hazrat Usman
None of these

Correct Answer Logic:

Fought in 642 CE, it was a decisive victory for the Muslims during Hazrat Umar's era.

Uploaded by: Fani Warraich

Paper-I (Anatomy/Physiology and Biochemistry/Microbiology) QUESTION #3383

Question 8

'Atherosclerosis' is primarily associated with high levels of which lipoprotein?

HDL
LDL✔️
Chylomicrons
VLDL

Correct Answer Logic:

LDL is often called 'bad cholesterol' because it deposits fat in arterial walls.

Uploaded by: Fani Warraich

Pakistan Affairs QUESTION #298

Question 9

What significant impact was caused to Pakistan by direct Military rule?

Corrosion of civil liberties
Unstable civil institutions✔️
Economic stagnation
Encouragement of FDI

Correct Answer Logic:

Frequent interventions weakened the growth and stability of democratic institutions.+1

Uploaded by: Fani Warraich

Agronomy QUESTION #2064

Question 10

Zinc deficiency, the most widespread micronutrient deficiency in Pakistan and South Asia, is characterized by:

Dark green, crinkled older leaves with necrotic margins
Interveinal chlorosis and stunting of older leaves due to Zn mobility
Stunted young leaves, shortened internodes (little leaf/khaira disease in rice), interveinal chlorosis on young leaves, and delayed maturity — due to Zn's role in auxin synthesis and enzyme activation✔️
Pale yellow coloration of the entire plant with early senescence

Correct Answer Logic:

Zn deficiency causes little leaf/rosette in fruit trees, khaira disease in rice, and white bud in maize. Young leaves are affected first (Zn is relatively immobile in phloem). Zn activates >300 enzymes, is required for IAA synthesis, RNA polymerase, and ribosome structure. ZnSO₄ (21% Zn) applied at 25 kg/ha corrects deficiency.

Uploaded by: Fani Warraich

Biology QUESTION #7256

Question 11

ICBN stands for:

Indian Code of Botanical Nomenclature
Indian Congress of Biological Names
International Code of Botanical Nomenclature✔️
International Congress of Biological Names

Correct Answer Logic:

ICBN stands for International Code of Botanical Nomenclature. It is the set of rules governing the naming of plants, algae, and fungi. It ensures each plant has one accepted scientific name, following binomial nomenclature as proposed by Linnaeus. (Now updated to ICN — International Code of Nomenclature for algae, fungi, and plants.)

Uploaded by: Fani Warraich

Chemistry QUESTION #1010

Question 12

Identify the homoleptic complex(es) that is/are low spin. (A) $[\text{Fe(CN)}_5\text{NO}]^{2-}$ (B) $[\text{CoF}_6]^{3-}$ (C) $[\text{Fe(CN)}_6]^{4-}$ (D) $[\text{Co(NH}_3)_6]^{3+}$ (E) $[\text{Cr(H}_2\text{O)}_6]^{2+}$

(C) only
(C) and (D) only✔️
(A) and (C) only
(B) and (E) only

Correct Answer Logic:

Homoleptic = only one type of ligand. (A) has $\text{CN}^-$ and NO — not homoleptic. (B) $[\text{CoF}_6]^{3-}$: F is weak field → high spin. (C) $[\text{Fe(CN)}_6]^{4-}$: $\text{CN}^-$ is strong field → low spin, homoleptic. (D) $[\text{Co(NH}_3)_6]^{3+}$: $\text{NH}_3$ is moderate-strong field on $\text{Co}^{3+}$ → low spin, homoleptic. So (C) and (D) are both homoleptic and low spin.

Uploaded by: Fani Warraich

General Science and Ability QUESTION #201

Question 13

Cement factory labourers are prone to:

Leukemia
Cytosilicosis✔️
Bone marrow
None of these

Correct Answer Logic:

Silicosis (specifically cytosilicosis in some contexts) is caused by inhaling silica dust.

Uploaded by: Fani Warraich

General Abilities QUESTION #2852

Question 14

Find the area of a triangle with base 24 cm and height 10 cm.

110 cm²
120 cm²✔️
130 cm²
240 cm²

Correct Answer Logic:

Area of triangle $= \dfrac{1}{2} \times \text{base} \times \text{height} = \dfrac{1}{2} \times 24 \times 10 = 120 \text{ cm}^2$.

Uploaded by: Fani Warraich

Nursing QUESTION #9253

Question 15

A 3-year-old child weighing 12 kg is prescribed IV fluid for dehydration. Using the Holliday-Segar method, what is the CORRECT daily maintenance fluid requirement?

800 mL/day
1100 mL/day✔️
1200 mL/day
1500 mL/day

Correct Answer Logic:

The Holliday-Segar method calculates maintenance fluid requirements:

Weight	Fluid Rate
First 10 kg	$100\,\text{mL/kg/day}$
Next 10 kg (10–20 kg)	$50\,\text{mL/kg/day}$
Each kg above 20 kg	$20\,\text{mL/kg/day}$

Calculation for 12 kg child:

\[\text{First 10 kg} = 10 \times 100 = 1000\,\text{mL}\]

\[\text{Next 2 kg} = 2 \times 50 = 100\,\text{mL}\]

\[\text{Total} = 1000 + 100 = 1100\,\text{mL/day}\]

Hourly rate: $\dfrac{1100}{24} \approx 46\,\text{mL/hr}$

This formula is essential for pediatric nurses. Remember: it calculates maintenance only — deficit and ongoing losses are added separately in dehydrated children.

Uploaded by: Fani Warraich

Verbal Reasoning QUESTION #8081

Question 16

$(19 - 18 - 17 - 16) - (20 - 19 - 18 - 17) =$

$-36$
$-6$
$-4$
$1$✔️

Correct Answer Logic:

Calculate each parenthesis separately:

First: $(19 - 18 - 17 - 16) = 19 - 18 - 17 - 16 = 1 - 17 - 16 = -16 - 16 = -32$

Second: $(20 - 19 - 18 - 17) = 20 - 19 - 18 - 17 = 1 - 18 - 17 = -17 - 17 = -34$

Now subtract: $(-32) - (-34) = -32 + 34 = 2$

Wait, let me recalculate more carefully:

$(19 - 18 - 17 - 16) = 19 - 51 = -32$

$(20 - 19 - 18 - 17) = 20 - 54 = -34$

$(-32) - (-34) = -32 + 34 = 2$

Hmm, 2 is not among the options. Let me check the arithmetic again:

$19 - 18 = 1$, $1 - 17 = -16$, $-16 - 16 = -32$ ✓

$20 - 19 = 1$, $1 - 18 = -17$, $-17 - 17 = -34$ ✓

$-32 - (-34) = 2$

Since the given answer is D, which corresponds to index 3 (value 1), there may be an error in my reading or the answer key. But mathematically, the answer is 2.

Uploaded by: Fani Warraich

General Knowledge QUESTION #8740

Question 17

What was the name of the first space shuttle launched by the United States on April 12, 1981?

Discovery
Endeavor
Columbia✔️
Atlantis

Correct Answer Logic:

Columbia was the first space shuttle to fly.

Uploaded by: Fani Warraich

Civil Engineering QUESTION #2126

Question 18

The hydraulic grade line (HGL) and energy grade line (EGL) in pipe flow are related such that:

HGL is always above EGL by the velocity head
EGL is always above or equal to HGL by the velocity head $\dfrac{V^2}{2g}$ — the vertical distance between EGL and HGL equals the velocity head at any cross-section✔️
HGL and EGL coincide for all flows
EGL slopes upward in the direction of flow while HGL slopes downward

Correct Answer Logic:

EGL represents total energy head $= \dfrac{p}{\rho g} + z + \dfrac{V^2}{2g}$. HGL represents piezometric head $= \dfrac{p}{\rho g} + z$. The difference is the velocity head: $EGL - HGL = \dfrac{V^2}{2g}$. Both slope downward in flow direction (energy loss). EGL is always above HGL (except at stagnation). When HGL falls below pipe centerline, pressure becomes sub-atmospheric — risk of cavitation and column separation.

Uploaded by: Fani Warraich

Mathematics QUESTION #6011

Question 19

Identify the curve from the family defined by $(x^2-y^2)\,dx + 2xy\,dy = 0$ that passes through the point $(1,1)$.

A circle centred on the $x$-axis
An ellipse with major axis along the $y$-axis
A circle centred on the $y$-axis✔️
A hyperbola with transverse axis along the $x$-axis

Correct Answer Logic:

Rewrite: $\frac{dy}{dx} = \frac{y^2-x^2}{2xy}$. This is a homogeneous ODE. Let $y=vx$:

$\frac{1-v^2}{2v}dx + x\,dv/... $

After solving, the general solution is $x^2 + y^2 = Cy$ (circles with centres on the $y$-axis).

Substituting $(1,1)$: $1+1=C\cdot1 \Rightarrow C=2$, giving $x^2+y^2=2y$, i.e. $x^2+(y-1)^2=1$.

This is a circle centred on the $y$-axis at $(0,1)$.

Uploaded by: Fani Warraich

Physics QUESTION #4388

Question 20

A projectile is launched in air with a certain angle; its velocity is maximum at:

Point of projection✔️
Highest point
Between launching and highest point
At all points

Correct Answer Logic:

At the point of projection, the projectile has both horizontal and vertical components of velocity. At the highest point, only the horizontal component remains. Since speed is greatest at the launch point, velocity magnitude is maximum there.

Uploaded by: Fani Warraich

More Options

Suggest a Question

Weight	Fluid Rate
First 10 kg	\(100\,\text{mL/kg/day}\)
Next 10 kg (10–20 kg)	\(50\,\text{mL/kg/day}\)
Each kg above 20 kg	\(20\,\text{mL/kg/day}\)