Reading Mode - Questions

Accounting & Finance QUESTION #6233

Question 1

Which ethical principle prevents an auditor from using client information for personal gain?

Integrity
Professional Behavior
Confidentiality✔️
Due Care

Correct Answer Logic:

Confidentiality dictates that the auditor should not disclose info without permission nor use it for personal benefit.

Uploaded by: Fani Warraich

Mathematics QUESTION #6024

Question 2

If $y = \sec(\tan^{-1}x)$, find $\dfrac{dy}{dx}$ at $x=1$.

$\dfrac{1}{\sqrt{2}}$✔️
$\dfrac{1}{2}$
1
$\sqrt{2}$

Correct Answer Logic:

Let $\theta = \tan^{-1}x$, so $\tan\theta = x$ and $y = \sec\theta$.

$\frac{dy}{dx} = \sec\theta\tan\theta\cdot\frac{d\theta}{dx} = \sec\theta\tan\theta\cdot\frac{1}{1+x^2}$

Since $\tan\theta=x$ and $\sec\theta=\sqrt{1+x^2}$:

$\frac{dy}{dx} = \sqrt{1+x^2}\cdot x\cdot\frac{1}{1+x^2} = \frac{x}{\sqrt{1+x^2}}$

At $x=1$: $\frac{dy}{dx} = \frac{1}{\sqrt{2}}$

Uploaded by: Fani Warraich

CISA QUESTION #6823

Question 3

In a risk-based audit approach, an auditor must choose between auditing a low-risk system with known minor issues or a high-risk system with uncertain status. Which decision BEST reflects risk-based methodology?

Audit the low-risk system because issues are known
Audit the high-risk system because uncertainty represents greater potential exposure✔️
Audit both systems simultaneously
Audit neither until more information is available

Correct Answer Logic:

Risk-based auditing prioritizes resources toward highest-risk areas with greatest potential impact. Uncertain status in a high-risk system represents significant potential exposure that must be investigated. Known minor issues in low-risk systems, while needing attention, pose less organizational threat.

Uploaded by: Fani Warraich

Ability / HR / Governance / Special Education QUESTION #1896

Question 4

Under Rule 3(c)(ii) which lifestyle indicator can make a government servant liable to be considered corrupt?

Owning a vehicle
Residing in a government house
Assuming a style of living beyond his ostensible means✔️
Travelling abroad on official duty

Correct Answer Logic:

Rule 3(c)(ii) specifically mentions assuming a style of living beyond ostensible means as a corruption indicator.

Uploaded by: Fani Warraich

Academic/Professional (Social Sciences) QUESTION #10143

Question 5

A study measures literacy rates across the national population every year for a decade, without tracking specific individuals. This is best classified as a:

Panel study
Time-series study✔️
Cohort study
Ethnographic study

Correct Answer Logic:

Repeated population-level measurement without following the same individuals defines a time-series study.

Uploaded by: Fani Warraich

Ability / HR / Governance / Special Education QUESTION #5645

Question 6

A post in any office or department has remained vacant for three years or more continuously. What is the consequence under the delegated financial powers in Annex-I?

The post is automatically converted to a Development Expenditure post
The post shall be deemed to have been abolished and revival requires prior approval of the Financial Adviser✔️
The Secretary has full powers to revive the post without any prior approval
The post can be revived by the Head of Department within his delegated powers

Correct Answer Logic:

Per Annex-I remarks the post in any office or department which has remained vacant for a period of three years or more shall be deemed to have been abolished. The powers for revival of that post shall not be exercised without obtaining prior approval of the Financial Adviser.

Uploaded by: Fani Warraich

Nursing QUESTION #9142

Question 7

During intrapartum monitoring, a CTG strip shows: baseline FHR 155 bpm, variability 2 bpm, late decelerations after each contraction recovering within 30 seconds. This CTG is classified as:

Normal/Reassuring
Suspicious/Non-reassuring
Pathological✔️
Technically unsatisfactory

Correct Answer Logic:

CTG classification is based on NICE (2022) / FIGO guidelines. Assess 4 features:

Feature	Reassuring	Non-reassuring	Abnormal	This Strip
Baseline FHR	110–160 bpm	100–109 or 161–180	<100 or >180	155 bpm ✓ Reassuring
Variability	5–25 bpm	3–4 bpm (>30 min) or >25 bpm	<3 bpm (>60 min) or sinusoidal	2 bpm = Abnormal
Decelerations	None or early	Variable (typical)	Late decelerations	Late = Abnormal
Accelerations	Present	Absent	—	Not mentioned

Classification (NICE):

Normal: All 4 features reassuring
Suspicious: 1 non-reassuring feature
Pathological: ≥2 non-reassuring OR ≥1 abnormal feature

This CTG has: variability 2 bpm (abnormal) + late decelerations (abnormal) = PATHOLOGICAL

Action: Inform senior doctor immediately, consider fetal blood sampling (FBS), prepare for expedited delivery. Offer resuscitative measures: maternal lateral position, IV fluids, stop oxytocin.

Uploaded by: Fani Warraich

FIA Act QUESTION #10002

Question 8

Under the Act's scheme, which authority combination is required before an unauthorized Sub-Inspector-rank member can lawfully arrest without a warrant under Section 5(3)?

Rank + reasonable suspicion only
Rank + DG authorization + reasonable suspicion of a Section 3(1) offence✔️
DG authorization alone, rank immaterial
Provincial Government concurrence only

Correct Answer Logic:

Section 5(3) cumulatively requires adequate rank, DG authorization, and reasonable suspicion of a scheduled offence.

Uploaded by: Fani Warraich

Physics QUESTION #7005

Question 9

A satellite orbits at height $h$ from Earth's surface where $h \ll R$ ($R$ = Earth's radius). The minimum increase in speed for the satellite to escape Earth's gravitational field is:

$\sqrt{2gR}$
$\sqrt{gR}$
$\sqrt{\dfrac{gR}{2}}$
$\sqrt{gR}\,(\sqrt{2}-1)$✔️

Correct Answer Logic:

For $h \ll R$, orbital radius $\approx R$:

Orbital speed: $v_o = \sqrt{gR}$

Escape speed from surface (approximately same radius): $v_e = \sqrt{2gR}$

Minimum increase: $\Delta v = v_e - v_o = \sqrt{2gR} - \sqrt{gR} = \sqrt{gR}(\sqrt{2}-1)$

Uploaded by: Fani Warraich

Mathematics QUESTION #1321

Question 10

The area enclosed between two curves $y=f(x)$ and $y=g(x)$ where $f(x)\geq g(x)$ on $[a,b]$ is given by:

$\int_a^b[f(x)+g(x)]\,dx$
$\int_a^b[f(x)-g(x)]\,dx$✔️
$\int_a^b[f(x)\cdot g(x)]\,dx$
$\dfrac{1}{2}\int_a^b[f(x)-g(x)]\,dx$

Correct Answer Logic:

The area between two curves is the integral of the top curve minus the bottom curve: $A=\int_a^b[f(x)-g(x)]\,dx$ where $f(x)\geq g(x)$ on $[a,b]$. The limits $a$ and $b$ are the $x$-coordinates of the intersection points.

Uploaded by: Fani Warraich

Agronomy QUESTION #2105

Question 11

C4 photosynthesis confers agronomic advantages over C3 photosynthesis under high temperature and high irradiance conditions primarily because:

C4 plants have more chlorophyll and larger leaves than C3 plants
The C4 CO₂-concentrating mechanism (using PEP carboxylase in mesophyll cells to fix CO₂ as oxaloacetate/malate, then decarboxylating in bundle sheath cells to deliver high CO₂ to Rubisco) suppresses photorespiration and allows near-maximum photosynthesis at high temperatures when Rubisco oxygenase activity would otherwise dominate✔️
C4 plants have deeper root systems that access subsoil water inaccessible to C3 plants
C4 plants fix nitrogen more efficiently, requiring less protein investment in Rubisco

Correct Answer Logic:

At high temperatures, Rubisco's oxygenase activity (photorespiration) increases relative to carboxylase in C3 plants, wasting 30–50% of fixed carbon. C4 plants pump CO₂ to bundle sheath cells at 10–80× atmospheric concentration, suppressing oxygenase competition and photorespiration. This gives C4 crops (maize, sorghum, sugarcane, millet) higher radiation use efficiency, WUE, and NUE under tropical conditions.

Uploaded by: Fani Warraich

Physics QUESTION #6989

Question 12

A parallel plate capacitor of capacitance 90 pF is connected to a 20 V battery. A dielectric slab with dielectric constant $K = \dfrac{5}{3}$ is then inserted between the plates. What is the magnitude of the induced (bound) charge on the dielectric?

2.4 nC
0.9 nC
1.2 nC✔️
0.3 nC

Correct Answer Logic:

Initial charge (without dielectric):

$Q_0 = C_0 V = 90 \times 10^{-12} \times 20 = 1800\ \text{pC} = 1.8\ \text{nC}$

New capacitance with dielectric:

$C = KC_0 = \frac{5}{3} \times 90 = 150\ \text{pF}$

New free charge:

$Q = CV = 150 \times 10^{-12} \times 20 = 3000\ \text{pC} = 3\ \text{nC}$

Induced charge on dielectric:

$Q_{induced} = Q\left(1 - \frac{1}{K}\right) = 3 \times \left(1 - \frac{3}{5}\right) = 3 \times \frac{2}{5} = 1.2\ \text{nC}$

Uploaded by: Fani Warraich

Paper-II (Pharmacognosy and Pharmaceutics-I) QUESTION #3593

Question 13

'Ephedrine' is an alkaloid used primarily as a:

Bronchodilator✔️
Painkiller
Antibiotic
Purgative

Correct Answer Logic:

Ephedrine is used to treat asthma and nasal congestion.

Uploaded by: Fani Warraich

Physics and Math QUESTION #783

Question 14

If $ax^2 + 2hxy + by^2 = 0$, their lines are orthogonal when:

$a + b = 0$✔️
$a - b = 0$
$a = b$
None

Correct Answer Logic:

For the pair of lines $ax^2 + 2hxy + by^2 = 0$ to be perpendicular, the sum of coefficients of $x^2$ and $y^2$ must be zero: $a + b = 0$.

Uploaded by: Fani Warraich

MCQs Section QUESTION #4905

Question 15

A number of linguists contend _____ can be traced back to a common root language.

that all of the thousands of languages spoken by the world's five billion people can be traced✔️
that the world's five billion people speak thousands of languages of which all can be traced
the world's five billion people speak thousands of languages which are all traceable
all of the thousands of languages spoken by the world's five billion people to be traceable

Correct Answer Logic:

Contend that…can be traced' is the proper construction after a verb of assertion. Option D omits 'that' and uses an awkward infinitive. Option E turns the contention into an ability claim. Options B and C shift the focus unnecessarily from the languages to the speakers.

Uploaded by: Fani Warraich

Molecular Biology / Bioinformatics / Biochemistry QUESTION #11066

Question 16

Polymorphism is a characteristic feature of which phylum?

Cnidaria✔️
Nematoda
Annelida
None of these

Correct Answer Logic:

Polymorphism — the existence of two or more structurally and functionally different individual types (zooids) within the same species colony — is a hallmark of Cnidaria. Colonial cnidarians (e.g. Physalia — Portuguese man-o'-war, Obelia) have polymorphic zooids: polyps (sessile, for feeding/reproduction: hydranths, gonozooids, dactylozooids) and medusae (free-swimming, for sexual reproduction). Each zooid type is structurally adapted for its specific function.

Uploaded by: Fani Warraich