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JEE MAIN Chemistry QUESTION #1020
Question 1
Arrange \(\text{HBr}\), \(\text{H}_2\text{S}\), \(\text{NF}_3\) and \(\text{CHCl}_3\) in increasing order of their dipole moment:
  • \(\text{H}_2\text{S} < \text{HBr} < \text{NF}_3 < \text{CHCl}_3\)
  • \(\text{NF}_3 < \text{HBr} < \text{H}_2\text{S} < \text{CHCl}_3\)✔️
  • \(\text{HBr} < \text{H}_2\text{S} < \text{NF}_3 < \text{CHCl}_3\)
  • \(\text{CHCl}_3 < \text{NF}_3 < \text{HBr} < \text{H}_2\text{S}\)
Correct Answer Explanation
Dipole moments (approx): \(\text{NF}_3\approx0.24\ \text{D}\) (F pulls away from N lone pair, net dipole is small); \(\text{HBr}\approx0.82\ \text{D}\); \(\text{H}_2\text{S}\approx0.97\ \text{D}\); \(\text{CHCl}_3\approx1.87\ \text{D}\). Increasing order: \(\text{NF}_3 < \text{HBr} < \text{H}_2\text{S} < \text{CHCl}_3\).