Home › MCQs › NEET Chemistry › Question #1075
Back to Questions
NEET Chemistry QUESTION #1075
Question 1
The oxidation states of the underlined elements in \(\underline{\text{K}}\text{O}_2\), \(\text{H}_2\underline{\text{O}}_2\) and \(\text{H}_2\underline{\text{S}}\text{O}_4\) are respectively:
  • \(+1, -2,\) and \(+4\)
  • \(+4, -4,\) and \(+6\)
  • \(+1, -1,\) and \(+6\)✔️
  • \(+2, -2,\) and \(+6\)
Correct Answer Explanation
In KO\(_2\) (potassium superoxide): K is +1, O\(_2^-\) so O is \(-\frac{1}{2}\)... but underlined is K: \(+1\). In H\(_2\)O\(_2\): underlined O has oxidation state \(-1\). In H\(_2\)SO\(_4\): underlined S has oxidation state \(+6\). So the answer is \(+1, -1, +6\).