2-Methylbutane has distinct H environments: (1) 6H on two equivalent CH\(_3\) (C1,C1'), (2) 1H on CH (C2) — chiral center created → 2 enantiomers, (3) 2H on CH\(_2\) (C3) — creates chiral center → 2 enantiomers, (4) 3H on terminal CH\(_3\) (C4) → 1 product. Total distinct products including stereoisomers: 1+2+2+1 = ... but checking: C1 gives 1 product (no new chiral center since both methyls equivalent), C2 gives 1 achiral product (actually a meso consideration), C3 gives 2 enantiomers, C4 gives 1. Total = 5.