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NEET Chemistry QUESTION #1085
Question 1
For the reaction \(\text{C(s)} + 2\text{H}_2\text{(g)} \to \text{CH}_4\text{(g)}\); \(\Delta H = -74.8\ \text{kJ mol}^{-1}\). Which diagram accurately represents this reaction?
  • Diagram with R higher than P by 74.8, with activation energy hump above R
  • Diagram with P higher than R by 74.8, with R lower
  • Diagram with R and P at same level, hump of 74.8 above
  • Diagram with P lower than R by 74.8 kJ, hump above R then drop to P✔️
Correct Answer Explanation
Since \(\Delta H = -74.8\ \text{kJ mol}^{-1}\) (exothermic), products (P) are lower in energy than reactants (R) by 74.8 kJ. The diagram should show R at higher energy, a transition state hump above R, then P at lower energy with the difference being 74.8 kJ. Option (4) correctly shows this: R is lower baseline, hump above, P drops 74.8 below R.