For text A(g) rightleftharpoons 2text B(g) , backward rate constant is 2500 times forward rate constant at 1000 K. K_p at 1000 K is: (R = 0.0831 L atm mol^ -1 K^ -1 )

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NEET Chemistry QUESTION #1088

Question 1

For \(\text{A(g)} \rightleftharpoons 2\text{B(g)}\), backward rate constant is 2500 times forward rate constant at 1000 K. \(K_p\) at 1000 K is: (R = 0.0831 L atm mol\(^{-1}\)K\(^{-1}\))

0.033✔️
0.021
83.1
\(2.077\times10^5\)

Correct Answer Explanation

\(K_c = \frac{k_f}{k_b} = \frac{1}{2500} = 4\times10^{-4}\). For \(\text{A}\rightleftharpoons 2\text{B}\): \(\Delta n = 2-1=1\). \(K_p = K_c(RT)^{\Delta n} = \frac{1}{2500}\times(0.0831\times1000)^1 = \frac{83.1}{2500} = 0.03324 \approx 0.033\).

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