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NEET Chemistry QUESTION #1089
Question 1
The ratio of wavelengths of light absorbed by hydrogen atom for \(n=2\to n=3\) and \(n=4\to n=6\) transitions is:
  • \(\dfrac{1}{9}\)
  • \(\dfrac{1}{4}\)✔️
  • \(\dfrac{1}{36}\)
  • \(\dfrac{1}{16}\)
Correct Answer Explanation
For hydrogen: \(\frac{1}{\lambda} = R_H\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)\). Transition 1 (\(n=2\to3\)): \(\frac{1}{\lambda_1}=R_H\left(\frac{1}{4}-\frac{1}{9}\right)=R_H\cdot\frac{5}{36}\). Transition 2 (\(n=4\to6\)): \(\frac{1}{\lambda_2}=R_H\left(\frac{1}{16}-\frac{1}{36}\right)=R_H\cdot\frac{5}{144}\). Ratio: \(\frac{\lambda_1}{\lambda_2}=\frac{5/144}{5/36}=\frac{36}{144}=\frac{1}{4}\).