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NEET Chemistry QUESTION #1108
Question 1
Match List I (Ion) with List II (Group in Cation Analysis): A. Co\(^{2+}\) B. Mg\(^{2+}\) C. Pb\(^{2+}\) D. Al\(^{3+}\); with I. Group-I II. Group-III III. Group-IV IV. Group-VI
  • A-III, B-II, C-IV, D-I
  • A-III, B-II, C-I, D-IV
  • A-III, B-IV, C-II, D-I
  • A-III, B-IV, C-I, D-II✔️
Correct Answer Explanation
In qualitative analysis: Pb\(^{2+}\) → Group I (precipitates as PbCl\(_2\) with HCl) but also appears partially in Group II. Co\(^{2+}\) → Group III (precipitates as CoS in NH\(_4\)OH/H\(_2\)S). Al\(^{3+}\) → Group III (Al(OH)\(_3\) precipitate). Mg\(^{2+}\) → Group VI (last group, Mg(OH)\(_2\) with NaOH). Pb\(^{2+}\) in Group IV (PbS with H\(_2\)S in dilute HCl). Matching: A-III, B-IV (Mg=Group VI? or IV), C-I (Pb=Group I), D-III... Revised: A(Co\(^{2+}\))=III, B(Mg\(^{2+}\))=IV (Group IV uses (NH\(_4\))\(_2\)CO\(_3\): no, Mg is Group V or VI). Standard: A-III, B-IV, C-I, D-II — option (4).