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Basic Mathematics
QUESTION #2825
Question 1
Solve the simultaneous equations: \(2x + 3y = 12\) and \(x - y = 1\).
Correct Answer Explanation
From \(x - y = 1\): \(x = y + 1\). Substitute into first equation: \(2(y+1) + 3y = 12 \Rightarrow 2y + 2 + 3y = 12 \Rightarrow 5y = 10 \Rightarrow y = 2\). Then \(x = 3\).
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