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MDCAT Physics QUESTION #4396
Question 1
In an ideal transformer, if the primary voltage is doubled and the turns ratio remains the same, what happens to the secondary current?
  • Doubles✔️
  • Halves
  • Remains the same
  • Becomes four times
Correct Answer Explanation
Transformer equation: $\dfrac{V_s}{V_p} = \dfrac{N_s}{N_p}$. If $V_p$ doubles and turns ratio stays same, $V_s$ doubles. Power $P = V_p I_p = V_s I_s$. If $V_s$ doubles and power is constant, $I_s$ halves. However, if input power doubles (due to doubled $V_p$), $I_s$ doubles. Per answer key: secondary current doubles.