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MDCAT Physics QUESTION #4400
Question 1
A phase difference of $90°$ is equal to:
  • $\pi$ radians
  • $\dfrac{\pi}{2}$ radians✔️
  • $\pi n$ radians
  • $\dfrac{\pi}{4}$ radians
Correct Answer Explanation
Converting degrees to radians: $\theta_{rad} = \theta_{deg} \times \dfrac{\pi}{180}$. So $90° = 90 \times \dfrac{\pi}{180} = \dfrac{\pi}{2}$ radians.