In the Carius method for halogen estimation, 180 mg of an organic compound produced 143.5 mg of AgCl. Calculate the percentage composition of chlorine in the compound. [Molar masses: Ag = 108, Cl = 35.5 text g,mol ^ -1 ]

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EEJ MAIN Chemistry QUESTION #5516

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In the Carius method for halogen estimation, 180 mg of an organic compound produced 143.5 mg of AgCl. Calculate the percentage composition of chlorine in the compound. [Molar masses: Ag = 108, Cl = 35.5 \(\text{g\,mol}^{-1}\)]

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Correct Answer Explanation

Molar mass of AgCl \(=108+35.5=143.5\,\text{g\,mol}^{-1}\). Moles of AgCl formed \(=\frac{143.5\,\text{mg}}{143500\,\text{mg/mol}}=\frac{143.5}{143500}=10^{-3}\,\text{mol}\). Each mole of AgCl corresponds to 1 mole of Cl. Mass of Cl \(=10^{-3}\times35.5\,\text{g}=0.0355\,\text{g}=35.5\,\text{mg}\). Percentage of Cl \(=\frac{35.5}{180}\times100=19.72\approx20\%\).

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