For a reaction following the Arrhenius equation, the plot of ln k vs frac 1 RT gives a straight line with slope (-y) units. The activation energy of the reaction is:

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EEJ MAIN Chemistry QUESTION #5532

Question 1

For a reaction following the Arrhenius equation, the plot of $\ln k$ vs $\frac{1}{RT}$ gives a straight line with slope $(-y)$ units. The activation energy of the reaction is:

$y/R$ units
$y$ units✔️
$yR$ units
$-y$ units

Correct Answer Explanation

Arrhenius equation: $\ln k = \ln A - \frac{E_a}{RT}$. Plotting $\ln k$ vs $\frac{1}{RT}$, the slope = $-E_a$. Given slope = $-y$, therefore $E_a = y$ units. (Note: if plotted against $\frac{1}{T}$, slope = $-E_a/R$, but here the x-axis is $\frac{1}{RT}$, so the R is already incorporated into the x-axis, making the slope directly equal to $-E_a$.)

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