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JEE MAIN Chemistry QUESTION #5537
Question 1
If the activation energy of a reaction is $80.9\ \text{kJ mol}^{-1}$, the fraction of molecules at 700 K having sufficient energy to react is $e^{-x}$. Find the value of $x$ (nearest integer). [Use $R = 8.31\ \text{J K}^{-1}\text{mol}^{-1}$]
  • 14✔️
  • 13
  • 12
  • 11
Correct Answer Explanation
The fraction of molecules with energy $\geq E_a$ is given by $f = e^{-E_a/RT}$. So $x = \frac{E_a}{RT} = \frac{80900}{8.31\times700} = \frac{80900}{5817} \approx 13.9 \approx 14$.