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EEJ MAIN Chemistry QUESTION #5555
Question 1
The hybridisation of Xe in $XeOF_4$ and the number of lone pairs on Xe are respectively:
  • $sp^3d^2$ and 1✔️
  • $sp^3d$ and 2
  • $sp^3d^2$ and 2
  • $sp^3d$ and 1
Correct Answer Explanation
In $XeOF_4$: Xe has 8 valence electrons. Bonds: 1 double bond to O + 4 single bonds to F = 5 bond pairs. Lone pairs on Xe = 1. Total electron pairs = 6 → $sp^3d^2$ hybridisation. Shape is square pyramidal. So hybridisation = $sp^3d^2$ and lone pairs = 1.