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JEE MAIN Chemistry QUESTION #5565
Question 1
When glucose is subjected to prolonged heating with HI, the final product obtained is:
  • Hexanoic acid
  • 6-Iodohexanal
  • $n$-Hexane✔️
  • 1-Hexene
Correct Answer Explanation
When glucose is treated with HI (hydroiodic acid) on prolonged heating, all the –OH groups are replaced by –I (forming hexaiodohexane), followed by reduction of C–I bonds. This ultimately gives $n$-hexane. This classic reaction confirmed the straight-chain structure of glucose.