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JEE MAIN Chemistry QUESTION #5579
Question 1
Iodoform ($CHI_3$) can be prepared by the iodoform test from all EXCEPT:
  • Ethyl methyl ketone ($CH_3COC_2H_5$)
  • Isopropyl alcohol ($(CH_3)_2CHOH$)
  • 3-Methyl-2-butanone ($CH_3COCH(CH_3)_2$)
  • Isobutyl alcohol ($(CH_3)_2CHCH_2OH$)✔️
Correct Answer Explanation
The iodoform test is positive for compounds with $CH_3CO–$ or $CH_3CH(OH)–$ groups. Ethyl methyl ketone has $CH_3CO–$ → positive. Isopropyl alcohol has $CH_3CH(OH)–$ → positive. 3-Methyl-2-butanone has $CH_3CO–$ → positive. Isobutyl alcohol ($(CH_3)_2CHCH_2OH$) is a primary alcohol without $CH_3CH(OH)–$ group → does NOT give iodoform test.