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EEJ MAIN Chemistry
QUESTION #5583
Question 1
Phenol reacts with KBr/KBrO₃ solution (which generates $Br_2$ in situ). The major product obtained is:
Correct Answer Explanation
The –OH group in phenol is a powerful ortho/para director and activates all three positions (2, 4, and 6). With excess $Br_2$ in water (generated from $KBr + KBrO_3$), all three activated positions undergo electrophilic aromatic substitution to give 2,4,6-tribromophenol as the major product (white precipitate).
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