Consider the following reduction potentials:Zn^ 2+ + 2e^ - rightarrow Zn(s); E^ 0 = -0.76text V Ca^ 2+ + 2e^ - rightarrow Ca(s); E^ 0 = -2.87text V Mg^ 2+ + 2e^ - rightarrow Mg(s); E^ 0 = -2.36text V Ni^ 2+ + 2e^ - rightarrow Ni(s); E^ 0 = -0.25text V What is the correct increasing order of the reducing power of these metals?

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EEJ MAIN Chemistry QUESTION #7109

Question 1

Consider the following reduction potentials:

$Zn^{2+} + 2e^{-} \rightarrow Zn(s)$; $E^{0} = -0.76\text{ V}$
$Ca^{2+} + 2e^{-} \rightarrow Ca(s)$; $E^{0} = -2.87\text{ V}$
$Mg^{2+} + 2e^{-} \rightarrow Mg(s)$; $E^{0} = -2.36\text{ V}$
$Ni^{2+} + 2e^{-} \rightarrow Ni(s)$; $E^{0} = -0.25\text{ V}$

What is the correct increasing order of the reducing power of these metals?

$Ca < Zn < Mg < Ni$
$Ni < Zn < Mg < Ca$✔️
$Zn < Mg < Ni < Ca$
$Ca < Mg < Zn < Ni$

Correct Answer Explanation

Reducing power is inversely proportional to the standard reduction potential ($E^0$). The more negative the $E^0$ value, the stronger the reducing agent. Comparing the values: $Ni$ (-0.25) is the weakest, followed by $Zn$ (-0.76), then $Mg$ (-2.36), and $Ca$ (-2.87) is the strongest.

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