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EEJ MAIN Chemistry QUESTION #7126
Question 1
What is the specific reaction intermediate formed during the addition of $HOCl$ (aqueous chlorine) to propene?
  • $CH_{3}-CH^{+}-CH_{2}-Cl$✔️
  • $CH_{3}-CH(OH)-CH_{2}^{+}$
  • $CH_{3}-CH(Cl)-CH_{2}^{+}$
  • $CH_{3}-CH^{-}-CH_{2}-Cl$
Correct Answer Explanation
The reaction follows Markovnikov's rule. The electrophile $Cl^+$ attacks the double bond of propene ($CH_3-CH=CH_2$) to form the more stable secondary carbocation: $CH_3-CH^+-CH_2-Cl$. Subsequently, the nucleophile $OH^-$ attacks this carbocation.