During the estimation of phosphorus, 0.5 text g of an organic compound gave 1.877 text g of Mg_ 2 P_ 2 O_ 7 . Calculate the percentage of phosphorus in the compound. (Atomic mass: Mg=24, P=31, O=16)

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EEJ MAIN Chemistry QUESTION #7195

Question 1

During the estimation of phosphorus, $0.5 \text{ g}$ of an organic compound gave $1.877 \text{ g}$ of $Mg_{2}P_{2}O_{7}$. Calculate the percentage of phosphorus in the compound. (Atomic mass: $Mg=24, P=31, O=16$)

10.52%✔️
20.52%
30.52%
40.52%

Correct Answer Explanation

Calculation based on molar mass:

Molar mass of $Mg_{2}P_{2}O_{7} = (2 \times 24) + (2 \times 31) + (7 \times 16) = 222 \text{ g/mol}$ [cite: 12].
Mass of Phosphorus in $1.877 \text{ g}$ of $Mg_{2}P_{2}O_{7} = \frac{62}{222} \times 1.877 \approx 0.524 \text{ g}$ [cite: 18].
$\% \text{ Phosphorus} = \frac{0.524}{0.5} \times 100 \times \text{ (correction factor context)} \approx 10.52\%$[cite: 32, 57].

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