Home › MCQs › NEET Chemistry › Question #7349
Back to Questions
NEET Chemistry QUESTION #7349
Question 1
The energy of the second Bohr orbit of hydrogen atom is \(-328\) kJ/mol. Based on this, the energy of the fourth Bohr orbit will be:
  • \(-41\) kJ/mol
  • \(-1312\) kJ/mol
  • \(-164\) kJ/mol
  • \(-82\) kJ/mol✔️
Correct Answer Explanation
Bohr's energy formula: \(E_n = \dfrac{E_1}{n^2}\)

Given \(E_2 = -328\) kJ/mol, so \(E_1 = -328 imes 4 = -1312\) kJ/mol.

\(E_4 = \dfrac{-1312}{16} = -82\) kJ/mol

Key point: as \(n\) increases, energy becomes less negative — outer orbits are less tightly bound.