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NEET Chemistry
QUESTION #7355
Question 1
The total number of atomic orbitals present in the fourth principal energy level (\(n = 4\)) of an atom is:
Correct Answer Explanation
Formula: Total orbitals in shell \(n\) = \(n^2\)
For \(n = 4\): \(4^2 = 16\) orbitals
Breakdown:
For \(n = 4\): \(4^2 = 16\) orbitals
Breakdown:
- 4s: 1 orbital
- 4p: 3 orbitals
- 4d: 5 orbitals
- 4f: 7 orbitals
- Total = 1+3+5+7 = 16
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