Two radiations have energies E_1 = 25 eV and E_2 = 50 eV. The relationship between their wavelengths lambda_1 and lambda_2 is:

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NEET Chemistry QUESTION #7356

Question 1

Two radiations have energies \(E_1 = 25\) eV and \(E_2 = 50\) eV. The relationship between their wavelengths \(\lambda_1\) and \(\lambda_2\) is:

\(\lambda_1 = \lambda_2\)
\(\lambda_1 = 2\lambda_2\)✔️
\(\lambda_1 = 4\lambda_2\)
\(\lambda_1 = \dfrac{1}{2}\lambda_2\)

Correct Answer Explanation

Using: \(E = \dfrac{hc}{\lambda}\), so \(\lambda \propto \dfrac{1}{E}\)

\(\dfrac{\lambda_1}{\lambda_2} = \dfrac{E_2}{E_1} = \dfrac{50}{25} = 2\)

Therefore \(\lambda_1 = 2\lambda_2\).

Higher energy photons have shorter wavelengths — a fundamental relationship from Planck's quantum theory.

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