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NEET Chemistry QUESTION #7362
Question 1
The correct set of four quantum numbers for the valence electron of rubidium (\(Z = 37\)) is:
  • 5, 0, 0, +½✔️
  • 5, 1, 0, +½
  • 5, 1, 1, +½
  • 6, 0, 0 +½
Correct Answer Explanation
Electronic configuration of Rb (Z=37):
[Kr] 5s¹

The valence electron is in the 5s subshell:
  • \(n = 5\)
  • \(\ell = 0\) (s-subshell)
  • \(m = 0\)
  • \(s = +\frac{1}{2}\)
So the quantum numbers are (5, 0, 0, +½).